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Notes
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1. Special case of result in text. 2. See the definition: should be exp(–  /2).3. Since | zk | = exp(kLog | z |) = | z |k). 4. For i1/3 = exp( i/6 + 1/3.2ki), k = 0, 1, 2.5. Integer multiples of 2 i in the variable of exp give no new values. |
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