GREAT ICOSAHEDRON,

{3, 5/2}  or  (3)5/2

  Definition and notation

The last of the four Kepler-Poinsot polyhedra is the great icosahedron, illustrated at right. It has intersecting triangular faces (indicated by the ‘3’ in the symbol), and each vertex figure is a regular pentagram {5/2}.

This is a beautiful polyhedron, but its structure is quite complex and hard to come to terms with. First observe that the polyhedron is inscribed in a regular icosahedron. This solid is in fact a stellation of the icosahedron – according to Wenninger, the sixteenth stellation!

Notice that the faces here are intersecting equilateral triangles. These are inscribed in the enclosing dodecahedron, and occur in parallel pairs. Here are some examples:

green face                red face             magenta face

Notice what happens here. In the icosahedron, opposite triangular faces lie in parallel planes, and each is related to the other in its orientation by a half turn. In the great icosahedron, correspondingly, there are two parallel triangular faces, each related to the other in orientation by a half turn.

If you look carefully at the above figure, you will notice that as well as triangular faces, there are also many regular pentagrams. These are not faces: they are induced sets of edges, with each edge occurring as the intersection of two triangular faces. Each vertex of the solid protrudes from the centre of one of these pentagrams.

We are now going to determine the number of vertices, edges and faces. As before, it is the whole triangles that make up the faces here, not the individual parts. Similarly, the vertices of the solid are where the (five) vertices of the triangle faces meet. And the edges are the long line segments joining the vertices.

How many faces, edges, vertices does it have? Can you explain the symbols above?
   Complete the table below (# stands for ‘number of’). Do you notice something strange about your last entry?

V # triangle faces, F E V – E + F

Check your answers ...













































   You should have obtained:

V # triangle faces, F E V – E + F
12 20 30 2

Since each triangular face corresponds to a face of the icosahedron, F = 20. And since the vertices coincide with the vertices of a regular icosahedron, the number of vertices of this solid is 12. For the edges, each of the 20 faces has three edges, giving a count of 3 x 20; since each edge is counted twice in this calculation, we deduce that E = 30. Again, the Euler number 2 reappears here.





MathWorld gives without proof some of the basic measurements of this polyhedron.



  Duality

Compare the values of V, E and F  for the great stellated dodecahedron and the great icosahedron studied earlier. Compare also the symbols for the solids. What do you notice. Does this indicate duality?






We observe that the great stellated dodecahedron has V = 20, E = 30, F = 12, while the great icosahedron has the dual values V = 12, E = 30, F = 20. The dual nature is also reflected in the symbols for the solids:

the great stellated dodecahedron  {5/2, 3), and

the great icosahedron  {3, 5/2}.

It is possible to construct a compound model of these two polyhedra, as at right. This shows the correspondence between the vertices of the great icosahedron, and the pentagonal star faces of the great stellated dodecahedron.


  Further properties

As with the Platonic solids, we can use this Java applet to play with each of the Archimedean solids. Use the applet to try to gain an understanding of the inter-relationships between the different parts of this fascinating solid.


 Play with the solid to get a feel of its complicated structure.
 Click the ‘All’ button to see the internal icosahedron.
 Adjust the applet to show just the red faces. How many are there? How are they related? Notice the pattern on each of these faces which is determined by the other faces. Write a description of this pattern.
  Now highlight just two colours, and place the solid so that one pair of parallel coloured faces is ‘edge on’. What does this tell us about the edges of the pattern on each face?
  Do some more experiments of your own. Contact the author if you make any surprising discoveries. We’ll add them to this page!


  Colour analysis of the solid

The most obvious way of colouring this solid is to use ten colours, one colour corresponding to each pair of parallel faces of the circumscribing icosahedron. Another suggestion is that made by Wenninger, of a colouring using just five colours. In either case, when making the model, we are faced with the difficult task of deciding how the facets are to be coloured on the net. We tackle here the more difficult five-colour option. The analysis will probably help our understanding of the structure of the great icosahedron itself. It arose because in my edition of Wenninger, there is a simple typo, but more importantly, the colours of the dimple triangles are omitted. To my slight embarrassment, these dimple triangles turn out to have the same colour as the triangle to which they are attached.

Let us start with the icosahedron. Six of the vertices are labelled 1, 2, 3, 4, 5, 6, and the opposite vertices are marked with a dash. The diagram below shows a colouring using just five colours. The Schlegel diagram in the middle will help us keep track of all the colours. (The large triangle is blue.) At right is the correspondingly coloured great icosahedron. The vertex 6 faces out; the opposite vertex 6' is hidden behind the figure. The colourings have been obtained by matching the great icosahedron faces with the faces of the icosahedron at left. Notice that the orientation of each great icosahedron triangle is reversed from its corresponding icosahedral triangle.

We can first list the defining planes and their colours. Entries in the final two columns are for the faces opposite to those in the first two columns.

Dodecahedron Great     Icosahedron         Dodecahedron Great     Icosahedron    
156
23'4
1'5'6'
2'34'
1'34
2'5'6
13'4'
256'
456
12'3
4'5'6'
1'23'
235'
1'4'6
2'3'5
146'
236
145'
2'3'6'
1'4'5
13'5
2'4'6
1'35'
246'
126
34'5
1'2'6'
3'45'
2'45
1'3'6
24'5'
136'
124'
3'5'6
1'2'4
356'
346
1'25
3'4'6'
12'5'

To further understand the colouring, we notice that each vertex is set in a pentagonal dimple. We seek to define in order the colours of the planes defining each vertex and its surrounding dimple. The dimple faces are easy. Taking vertex 6 as an example, we see that in the original icosahedron, this vertex is surrounded by a pentagonal pyramid with base 12345(1) and vertex 6. In the great icosahedron, vertex 6 is surrounded by pentagram 13524(6). By the method of construction, the colours correspond in a simple way: for example the orange 156 face of the icosahedron gives rise in the great icosahedron to the orange inward facing 24 face of the pentagram about vertex 6.

Thus for the great icosahedron, we have the following colouring of the dimples. The edge notation can be thought of as directed: moving in the indicated direction implies that the stated colour is on the left. For example, moving from 2 to 5 gives the red colour to the left of the path.

Vertex
1
2
3
4
5
6
1'
2'
3'
4'
5'
6'
Dimple colouring
25
15'
1'6
1'5
14
13
2'3
1'3'
12'
16'
1'2
1'4'
54'
5'6
65'
53
43'
35
36'
3'4
2'4'
6'2
26'
4'2'
4'6
64'
5'4
32'
3'6
52
6'4
46'
4'5
23'
6'3
2'5'
63'
4'3
42
2'6
62'
24
45'
6'5
56'
3'5'
34'
5'3'
3'2
31
21'
61'
2'1
41
5'2'
51'
6'1
5'1
4'1'
3'1'

Now let us try to find the ordered colours for the triangles around each vertex. Each vertex is the meeting point of five pentagrams. We list just the pentagram edges from a given vertex, repeating each. Notice that we can obtain the end vertices from the Schlegel diagram of the icosahedron by starting with the given vertex and ‘crossing two triangles’. We label each of the two edges at each vertex in the order they would appear by traversing the pentagram in an anticlockwise direction. Notice that the final six rows are obtained from the first six by reversing the order of the entries and dashing the components. Since by our labelling we have paired the ‘inner faces’ of the pentagrams, we can now add the colours from the above table.


Vertex
 
       
1
2'1
16'
6'1
15'
5'1
13
31
14
41
12'
2
1'2
24
42
25
52
23'
3'2
26'
6'2
21'
3
13
34'
4'3
36'
6'3
32'
2'3
35
53
31
4
14
42
24
45'
5'4
46'
6'4
43'
3'4
41
5
1'5
56'
6'5
54'
4'5
52
25
53
35
51'
6
1'6
62'
2'6
63'
3'6
64'
4'6
65'
5'6
61'
1'
21'
1'4'
4'1'
1'3'
3'1'
1'5
51'
1'6
61'
1'2
2'
12'
2'6
62'
2'3
32'
2'5'
5'2'
2'4'
4'2'
2'1
3'
1'3'
3'5'
5'3'
3'2
23'
3'6
63'
3'4
43'
3'1'
4'
1'4'
4'3
34'
4'6
64'
4'5
54'
4'2'
2'4'
4'1'
5'
15'
5'3'
3'5'
5'2'
2'5'
5'4
45'
5'6
65'
5'1
6'
16'
6'5
56'
6'4
46'
6'3
36'
6'2
26'
6'1

Finally, let’s try to put it all together. Here are pyramid nets for the vertices, all in colour. The information comes from the above two tables.

After all this, I really prefer the ten colour colouring! The above colouring does achieve five colours around each vertex, but around the dimples you obviously get adjacent faces having the same colour.

  Model making

The model of the small stellated dodecahedron is easy to make. See this construction page for some details.








  Vertex coordinates

It is a simple matter to derive a set of vertex coordinates for the great icosahedron. For, as we have seen, these vertices are just the vertices of a regular icosahedron. Hence from our previous work, we can take the 12 vertex coordinate sets to be:

(, 1, 0), (0, , 1), ( 1, 0, ).




References

MathWorld : http://mathworld.wolfram.com/GreatStellatedDodecahedron.html

Wikipedia : http://en.wikipedia.org/wiki/Great_icosahedron

Construction : Wenninger, M. J., Polyhedron models, Cambridge (1971).

                        Cundy, H. M., Rollett, A. P., Mathematical Models, Oxford (1962).